THÔNG TIN CHI TIẾT ĐỀ THI
ĐỀ THI Toán học
Số câu hỏi: 11
Thời gian làm bài: 19 phút
Mã đề: #1693
Lĩnh vực: Toán học
Nhóm: Toán 10 - Cung và góc lượng giác. Công thức lượng giác
Lệ phí:
Miễn phí
Lượt thi: 1813
Ôn tập trắc nghiệm Cung và góc lượng giác Toán Lớp 10 Phần 4
Câu 1
Tập nghiệm của phương trình \(% MathType!MTEF!2!1!+- % feaahqart1ev3aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn % hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr % 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9 % vqaqpepm0xbbG8FasPYRqj0-yi0dXdbba9pGe9xq-JbbG8A8frFve9 % Fve9Ff0dmeaabaqaciGacaGaaeqabaWaaeaaeaaakeaaciGGZbGaai % yAaiaac6gacaaIYaGaamiEaiabg2da9iGacohacaGGPbGaaiOBaiaa % dIhaaaa!3FC7! \sin 2x = \sin x\)là
A.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbbG8FasPYRqj0-yi0dXdbba9pGe9xq-JbbG8A8frFve9
% Fve9Ff0dmeaabaqaciGacaGaaeqabaWaaeaaeaaakeaacaWGtbGaey
% ypa0ZaaiWaaeaacaWGRbGaaGOmaiaabc8acaGG7aWaaSaaaeaacaqG
% apaabaGaaG4maaaacqGHRaWkcaWGRbGaaGOmaiaabc8adaabbaqaai
% aadUgacqGHiiIZcqWIKeIOaiaawEa7aaGaay5Eaiaaw2haaaaa!4982!
S = \left\{ {k2{\rm{\pi }};\frac{{\rm{\pi }}}{3} + k2{\rm{\pi }}\left| {k \in Z} \right.} \right\}\)
B.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbbG8FasPYRqj0-yi0dXdbba9pGe9xq-JbbG8A8frFve9
% Fve9Ff0dmeaabaqaciGacaGaaeqabaWaaeaaeaaakeaacaWGtbGaey
% ypa0ZaaiWaaeaacaWGRbGaaGOmaiaabc8acaGG7aWaaSaaaeaacaqG
% apaabaGaaG4maaaacqGHRaWkdaWcaaqaaiaadUgacaaIYaGaaeiWda
% qaaiaaiodaaaWaaqqaaeaacaWGRbGaeyicI4SaeSijHikacaGLhWoa
% aiaawUhacaGL9baaaaa!4A4F!
S = \left\{ {k2{\rm{\pi }};\frac{{\rm{\pi }}}{3} + \frac{{k2{\rm{\pi }}}}{3}\left| {k \in Z} \right.} \right\}\)
C.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbbG8FasPYRqj0-yi0dXdbba9pGe9xq-JbbG8A8frFve9
% Fve9Ff0dmeaabaqaciGacaGaaeqabaWaaeaaeaaakeaacaWGtbGaey
% ypa0ZaaiWaaeaacaWGRbGaaGOmaiaabc8acaGG7aGaeyOeI0YaaSaa
% aeaacaqGapaabaGaaG4maaaacqGHRaWkcaWGRbGaaGOmaiaabc8ada
% abbaqaaiaadUgacqGHiiIZcqWIKeIOaiaawEa7aaGaay5Eaiaaw2ha
% aaaa!4A6F!
S = \left\{ {k2{\rm{\pi }}; - \frac{{\rm{\pi }}}{3} + k2{\rm{\pi }}\left| {k \in Z} \right.} \right\}\)
D.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbbG8FasPYRqj0-yi0dXdbba9pGe9xq-JbbG8A8frFve9
% Fve9Ff0dmeaabaqaciGacaGaaeqabaWaaeaaeaaakeaacaWGtbGaey
% ypa0ZaaiWaaeaacaWGRbGaaGOmaiaabc8acaGG7aGaaeiWdiabgUca
% RiaadUgacaaIYaGaaeiWdmaaeeaabaGaam4AaiabgIGiolablssiIc
% Gaay5bSdaacaGL7bGaayzFaaaaaa!48B5!
S = \left\{ {k2{\rm{\pi }};{\rm{\pi }} + k2{\rm{\pi }}\left| {k \in Z} \right.} \right\}\)
Câu 2
Nghiệm của pt \(% MathType!MTEF!2!1!+- % feaahqart1ev3aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn % hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr % 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9 % vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x % fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaaeaaaaaaaaa8 % qaciGGZbGaaiyAaiaac6gacaWG4bGaeyypa0Jaai4eGmaalaaabaGa % aGymaaqaaiaaikdaaaaaaa!3D2C! \sin x = -\frac{1}{2}\)là:
A.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbqfgBHr
% xAU9gimLMBVrxEWvgarmWu51MyVXgaruWqVvNCPvMCG4uz3bqefqvA
% Tv2CG4uz3bIuV1wyUbqee0evGueE0jxyaibaieYlf9yrpgeu0dXdh9
% vqqj-hEeeu0xXdbba9frFj0-OqFfea0dXdd9vqai-hGuQ8kuc9pgc9
% q8qqaq-dir-f0-yqaiVgFr0xfr-xfr-xb9adbaqaaeGaciGaaiaabe
% qaamaaeaqbaaGcbaGaamiEaiabg2da9maalaaabaGaeqiWdahabaGa
% aG4maaaacqGHRaWkcaWGRbGaaGOmaiabec8aWbaa!465A!
x = \frac{\pi }{3} + k2\pi \)
B.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbqfgBHr
% xAU9gimLMBVrxEWvgarmWu51MyVXgaruWqVvNCPvMCG4uz3bqefqvA
% Tv2CG4uz3bIuV1wyUbqee0evGueE0jxyaibaieYlf9yrpgeu0dXdh9
% vqqj-hEeeu0xXdbba9frFj0-OqFfea0dXdd9vqai-hGuQ8kuc9pgc9
% q8qqaq-dir-f0-yqaiVgFr0xfr-xfr-xb9adbaqaaeGaciGaaiaabe
% qaamaaeaqbaaGcbaGaamiEaiabg2da9maalaaabaGaeyOeI0IaeqiW
% dahabaGaaGOnaaaacqGHRaWkcaWGRbGaaGOmaiabec8aWbaa!474A!
x = \frac{{ - \pi }}{6} + k2\pi \)
C.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbqfgBHr
% xAU9gimLMBVrxEWvgarmWu51MyVXgaruWqVvNCPvMCG4uz3bqefqvA
% Tv2CG4uz3bIuV1wyUbqee0evGueE0jxyaibaieYlf9yrpgeu0dXdh9
% vqqj-hEeeu0xXdbba9frFj0-OqFfea0dXdd9vqai-hGuQ8kuc9pgc9
% q8qqaq-dir-f0-yqaiVgFr0xfr-xfr-xb9adbaqaaeGaciGaaiaabe
% qaamaaeaqbaaGcbaGaamiEaiabg2da9maalaaabaGaeqiWdahabaGa
% aGOnaaaacqGHRaWkcaWGRbGaaGOmaiabec8aWbaa!465D!
x = \frac{\pi }{6} + k2\pi \)
D.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbqfgBHr
% xAU9gimLMBVrxEWvgarmWu51MyVXgaruWqVvNCPvMCG4uz3bqefqvA
% Tv2CG4uz3bIuV1wyUbqee0evGueE0jxyaibaieYlf9yrpgeu0dXdh9
% vqqj-hEeeu0xXdbba9frFj0-OqFfea0dXdd9vqai-hGuQ8kuc9pgc9
% q8qqaq-dir-f0-yqaiVgFr0xfr-xfr-xb9adbaqaaeGaciGaaiaabe
% qaamaaeaqbaaGcbaGaamiEaiabg2da9maalaaabaGaaGynaiabec8a
% WbqaaiaaiAdaaaGaey4kaSIaam4AaiaaikdacqaHapaCaaa!471C!
x = \frac{{5\pi }}{6} + k2\pi \)
Câu 3
Nghiệm của phương trình \(% MathType!MTEF!2!1!+- % feaahqart1ev3aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn % hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr % 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9 % vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x % fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaaeaaaaaaaaa8 % qaciGGJbGaai4BaiaacshacaWG4bGaey4kaSYaaOaaaeaacaaIZaaa % leqaaOGaaiiOaiabg2da9iaabccacaaIWaaaaa!3F2F! \cot x + \sqrt 3 \; = {\rm{ }}0\)là:
A.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamiEaiabg2
% da9maalaaabaGaeqiWdahabaGaaG4maaaacqGHRaWkcaWGRbGaaGOm
% aiabec8aWbaa!3ECC!
x = \frac{\pi }{3} + k2\pi \)
B.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamiEaiabg2
% da9maalaaabaGaeqiWdahabaGaaGOnaaaacqGHRaWkcaWGRbGaeqiW
% dahaaa!3E13!
x = \frac{\pi }{6} + k\pi \)
C.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamiEaiabg2
% da9iabgkHiTmaalaaabaGaeqiWdahabaGaaGOnaaaacqGHRaWkcaWG
% RbGaeqiWdahaaa!3F00!
x = - \frac{\pi }{6} + k\pi \)
D.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamiEaiabg2
% da9iabgkHiTmaalaaabaGaeqiWdahabaGaaG4maaaacqGHRaWkcaWG
% RbGaeqiWdahaaa!3EFD!
x = - \frac{\pi }{3} + k\pi \)
Câu 4
Nghiệm của phương trình \(% MathType!MTEF!2!1!+- % feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn % hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr % 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9 % vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x % fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaWaaOaaaeaaca % aIZaaaleqaaOGaey4kaSIaaG4maiGacshacaGGHbGaaiOBaiaadIha % cqGH9aqpcaaIWaaaaa!3E03! \sqrt 3 + 3\tan x = 0\) là:
A.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamiEaiabg2
% da9maalaaabaGaeqiWdahabaGaaG4maaaacqGHRaWkcaWGRbGaeqiW
% dahaaa!3E10!
x= \frac{\pi }{3} + k\pi \)
B.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamiEaiabg2
% da9maalaaabaGaeqiWdahabaGaaGOmaaaacqGHRaWkcaWGRbGaaGOm
% aiabec8aWbaa!3ECB!
x= \frac{\pi }{2} + k2\pi \)
C.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamiEaiabg2
% da9iabgkHiTmaalaaabaGaeqiWdahabaGaaGOnaaaacqGHRaWkcaWG
% RbGaeqiWdahaaa!3F00!
x= - \frac{\pi }{6} + k\pi \)
D.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamiEaiabg2
% da9maalaaabaGaeqiWdahabaGaaGOmaaaacqGHRaWkcaWGRbGaeqiW
% dahaaa!3E0F!
x = \frac{\pi }{2} + k\pi \)
Câu 5
Nghiệm của phương trình \(% MathType!MTEF!2!1!+- % feaahqart1ev3aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn % hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr % 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9 % vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x % fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaci4yaiaac+ % gacaGGZbGaamiEaiabg2da9iabgkHiTmaalaaabaGaaGymaaqaaiaa % ikdaaaaaaa!3D3D! \cos x = - \frac{1}{2}\)là:
A.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamiEaiabg2
% da9iabgglaXoaalaaabaGaeqiWdahabaGaaG4maaaacqGHRaWkcaWG
% RbGaaGOmaiabec8aWbaa!40B9!
x = \pm \frac{\pi }{3} + k2\pi \)
B.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamiEaiabg2
% da9iabgglaXoaalaaabaGaeqiWdahabaGaaGOnaaaacqGHRaWkcaWG
% RbGaaGOmaiabec8aWbaa!40BC!
x = \pm \frac{\pi }{6} + k2\pi \)
C.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aqaMjdvLHfij5gC1rhimfMBNvxyNvga7HxpCbxBGW
% LzYf2y7jdxWLgi9T3m9TYAYWfCPbsFamXvP5wqSXMqHnxAJn0BKvgu
% HDwzZbqefqvATv2CG4uz3bIuV1wyUbqedmvETj2BSbqefm0B1jxALj
% hiov2DaebbnrfifHhDYfgasaacH8YjY-vipgYlh9vqqj-hEeeu0xXd
% bba9frFj0-OqFfea0dXdd9vqai-hGuQ8kuc9pgc9q8qqaq-dir-f0-
% yqaiVgFr0xfr-xfr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGc
% baaeaaaaaaaaa8qacaWG4bGaeyypa0JaeyySae7aaSaaa8aabaWdbi
% aaikdacqaHapaCa8aabaWdbiaaiodaaaGaey4kaSIaam4Aaiaaikda
% cqaHapaCaaa!53AB!
x = \pm \frac{{2\pi }}{3} + k2\pi \)
D.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamiEaiabg2
% da9iabgglaXoaalaaabaGaeqiWdahabaGaaGOnaaaacqGHRaWkcaWG
% RbGaeqiWdahaaa!4000!
x = \pm \frac{\pi }{6} + k\pi \)
Câu 6
Nghiệm của phương trình \(% MathType!MTEF!2!1!+- % feaahqart1ev3aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn % hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr % 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9 % vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x % fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaci4yaiaac+ % gacaGGZbGaamiEaiabg2da9maalaaabaGaaGymaaqaaiaaikdaaaaa % aa!3C50! \cos x = \frac{1}{2}\)là:
A.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamiEaiabg2
% da9iabgglaXoaalaaabaGaeqiWdahabaGaaG4maaaacqGHRaWkcaWG
% RbGaaGOmaiabec8aWbaa!40B9!
x = \pm \frac{\pi }{3} + k2\pi \)
B.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamiEaiabg2
% da9iabgglaXoaalaaabaGaeqiWdahabaGaaGOnaaaacqGHRaWkcaWG
% RbGaaGOmaiabec8aWbaa!40BC!
x = \pm \frac{\pi }{6} + k2\pi \)
C.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamiEaiabg2
% da9iabgglaXoaalaaabaGaeqiWdahabaGaaGinaaaacqGHRaWkcaWG
% RbGaaGOmaiabec8aWbaa!40BA!
x = \pm \frac{\pi }{4} + k2\pi \)
D.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamiEaiabg2
% da9iabgglaXoaalaaabaGaeqiWdahabaGaaGOmaaaacqGHRaWkcaWG
% RbGaaGOmaiabec8aWbaa!40B8!
x = \pm \frac{\pi }{2} + k2\pi \)
Câu 7
Nghiệm của phương trình cosx = -1 là
A.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aqaMjcvLHfij5gC1rhimfMBNvxyNvga7HxpCbxAGS
% YACbxAG0hatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLnhiov2D
% Gi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr4rNCHb
% GeaGqiVCI8FfYJH8YrFfeuY-Hhbbf9v8qqaqFr0xc9pk0xbba9q8Wq
% FfeaY-biLkVcLq-JHqpepeea0-as0Fb9pgeaYRXxe9vr0-vr0-vqpW
% qaaeaabiGaciaacaqabeaadaqaaqaaaOqaaabaaaaaaaaapeGaamiE
% aiabg2da9iabec8aWjabgUcaRiaadUgacqaHapaCaaa!4952!
x = \pi + k\pi \)
B.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aqaM5cvLHfij5gC1rhimfMBNvxyNvga7HxpTWLzYf
% 2y7XfCPbsF7jtFRSMmCbxAG0hatCvAUfeBSjuyZL2yd9gzLbvyNv2C
% aerbuLwBLnhiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLD
% harqqtubsr4rNCHbGeaGqiVCI8FfYJH8YrFfeuY-Hhbbf9v8qqaqFr
% 0xc9pk0xbba9q8WqFfeaY-biLkVcLq-JHqpepeea0-as0Fb9pgeaYR
% Xxe9vr0-vr0-vqpWqaaeaabiGaciaacaqabeaadaqaaqaaaOqaaaba
% aaaaaaaapeGaamiEaiabg2da9iabgkHiTmaalaaapaqaa8qacqaHap
% aCa8aabaWdbiaaikdaaaGaey4kaSIaam4AaiaaikdacqaHapaCaaa!508A!
x = - \frac{\pi }{2} + k2\pi \)
C.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aqaMncvLHfij5gC1rhimfMBNvxyNvga7HxpCbxAGS
% YAYWfCPbsFamXvP5wqSXMqHnxAJn0BKvguHDwzZbqefqvATv2CG4uz
% 3bIuV1wyUbqedmvETj2BSbqefm0B1jxALjhiov2DaebbnrfifHhDYf
% gasaacH8YjY-vipgYlh9vqqj-hEeeu0xXdbba9frFj0-OqFfea0dXd
% d9vqai-hGuQ8kuc9pgc9q8qqaq-dir-f0-yqaiVgFr0xfr-xfr-xb9
% adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaaeaaaaaaaaa8qacaWG
% 4bGaeyypa0JaeqiWdaNaey4kaSIaam4AaiaaikdacqaHapaCaaa!4A41!
x = \pi + k2\pi \)
D.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aqaM1cvLHfij5gC1rhimfMBNvxyNvga7HxpCzMCHn
% 2EZWfCPbsF7jtFRSgxWLgi9bWexLMBbXgBcf2CPn2qVrwzqf2zLnha
% ruavP1wzZbItLDhis9wBH5garmWu51MyVXgaruWqVvNCPvMCG4uz3b
% qee0evGueE0jxyaibaieYlNi-xH8yiVC0xbbL8F4rqqrFfpeea0xe9
% Lq-Jc9vqaqpepm0xbbG8FasPYRqj0-yi0dXdbba9pGe9xq-JbbG8A8
% frFve9Fve9Ff0dmeaabaqaciGacaGaaeqabaWaaeaaeaaakeaaqaaa
% aaaaaaWdbiaadIhacqGH9aqpdaWcaaWdaeaapeGaaG4maiabec8aWb
% WdaeaapeGaaGOmaaaacqGHRaWkcaWGRbGaeqiWdahaaa!4F71!
x = \frac{{3\pi }}{2} + k\pi \)
Câu 8
Nghiệm của phương trình cosx = 1 là:
A.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamiEaiabg2
% da9iaadUgacqaHapaCaaa!3AA3!
x= k\pi \)
B.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamiEaiabg2
% da9maalaaabaGaeqiWdahabaGaaGOmaaaacqGHRaWkcaWGRbGaaGOm
% aiabec8aWbaa!3ECA!
x= \frac{\pi }{2} + k2\pi \)
C.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamiEaiabg2
% da9iaadUgacaaIYaGaeqiWdahaaa!3B5F!
x = k2\pi \)
D.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamiEaiabg2
% da9maalaaabaGaeqiWdahabaGaaGOmaaaacqGHRaWkcaWGRbGaeqiW
% dahaaa!3E0E!
x = \frac{\pi }{2} + k\pi \)
Câu 9
Nghiệm của phương trình \(% MathType!MTEF!2!1!+- % feaahqart1ev3aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn % hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr % 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9 % vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x % fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaci4CaiaacM % gacaGGUbGaamiEaiabg2da9maalaaabaGaaGymaaqaaiaaikdaaaaa % aa!3C55! \sin x = \frac{1}{2}\) là
A.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamiEaiabg2
% da9maalaaabaGaeqiWdahabaGaaG4maaaacqGHRaWkcaWGRbGaaGOm
% aiabec8aWbaa!3ECB!
x= \frac{\pi }{3} + k2\pi \)
B.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamiEaiabg2
% da9maalaaabaGaeqiWdahabaGaaGOnaaaacqGHRaWkcaWGRbGaeqiW
% dahaaa!3E12!
x= \frac{\pi }{6} + k\pi \)
C.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamiEaiabg2
% da9iaadUgacqaHapaCaaa!3AA3!
x = k\pi \)
D.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamiEaiabg2
% da9maalaaabaGaeqiWdahabaGaaGOnaaaacqGHRaWkcaWGRbGaaGOm
% aiabec8aWbaa!3ECE!
x = \frac{\pi }{6} + k2\pi \)
Câu 10
Nghiệm của phương trình \(% MathType!MTEF!2!1!+- % feaahqart1ev3aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn % hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr % 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9 % vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x % fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaci4CaiaacM % gacaGGUbGaamiEaiabg2da9iabgkHiTiaaigdaaaa!3C76! \sin x = - 1\) là
A.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamiEaiabg2
% da9iabgkHiTmaalaaabaGaeqiWdahabaGaaGOmaaaacqGHRaWkcaWG
% RbGaeqiWdahaaa!3EFB!
x = - \frac{\pi }{2} + k\pi \)
B.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamiEaiabg2
% da9iabgkHiTmaalaaabaGaeqiWdahabaGaaGOmaaaacqGHRaWkcaWG
% RbGaaGOmaiabec8aWbaa!3FB7!
x = - \frac{\pi }{2} + k2\pi \)
C.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamiEaiabg2
% da9iaadUgacqaHapaCaaa!3AA3!
x= k\pi \)
D.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamiEaiabg2
% da9maalaaabaGaaG4maiabec8aWbqaaiaaikdaaaGaey4kaSIaam4A
% aiabec8aWnaalaaabaGaeyOeI0IaamOyaiabgglaXoaakaaabaGaam
% OyamaaCaaaleqabaGaaGOmaaaakiabgkHiTiaaisdacaWGHbGaam4y
% aaWcbeaaaOqaaiaaikdacaWGHbaaaaaa!49B7!
x = \frac{{3\pi }}{2} + k\pi\)
Câu 11
Nghiệm của phương trình sinx = 1 là:
A.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamiEaiabg2
% da9iabgkHiTmaalaaabaGaeqiWdahabaGaaGOmaaaacqGHRaWkcaWG
% RbGaaGOmaiabec8aWbaa!3FB7!
x = - \frac{\pi }{2} + k2\pi \)
B.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamiEaiabg2
% da9maalaaabaGaeqiWdahabaGaaGOmaaaacqGHRaWkcaWGRbGaeqiW
% dahaaa!3E0E!
x= \frac{\pi }{2} + k\pi \)
C.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamiEaiabg2
% da9iaadUgacqaHapaCaaa!3AA3!
x = k\pi \)
D.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamiEaiabg2
% da9maalaaabaGaeqiWdahabaGaaGOmaaaacqGHRaWkcaWGRbGaaGOm
% aiabec8aWbaa!3ECA!
x= \frac{\pi }{2} + k2\pi \)