THÔNG TIN CHI TIẾT ĐỀ THI
ĐỀ THI Toán học
Số câu hỏi: 50
Thời gian làm bài: 90 phút
Mã đề: #5103
Lĩnh vực: Toán học
Nhóm: THI THPTQG
Lệ phí:
Miễn phí
Lượt thi: 2707
Đề thi thử tốt nghiệp THPT QG môn Toán năm 2020
Câu 1
Cho số thực dương a > 0 và khác 1 . Hãy rút gọn biểu thức:
A.
P = 1 + a
B.
1
C.
a
D.
1 - a
Câu 2
Hình chóp tứ giác đều có bao nhiêu mặt phẳng đối xứng?
A.
2
B.
6
C.
8
D.
4
Câu 3
Tìm tất cả các giá trị thực của tham số m để hàm số \(% MathType!MTEF!2!1!+-
% feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamyEaiabg2
% da9iaad2gacaWG4bGaeyOeI0Iaci4CaiaacMgacaGGUbGaamiEaaaa
% !3EA9!
y = mx - \sin x\) đồng biến trên R .
A.
m > 1
B.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamyBaiabgs
% MiJkabgkHiTiaaigdaaaa!3A42!
m \le - 1\)
C.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamyBaiabgw
% MiZkaaigdaaaa!3966!
m \ge 1\)
D.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamyBaiabgw
% MiZkabgkHiTiaaigdaaaa!3A53!
m \ge - 1\)
Câu 4
Giá trị cực tiểu của hàm số \(% MathType!MTEF!2!1!+-
% feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamyEaiabg2
% da9iaadIhadaahaaWcbeqaaiaaiodaaaGccqGHsislcaaIZaGaamiE
% amaaCaaaleqabaGaaGOmaaaakiabgkHiTiaaiMdacaWG4bGaey4kaS
% IaaGOmaaaa!41CE!
y = {x^3} - 3{x^2} - 9x + 2\) là
A.
-20
B.
7
C.
-25
D.
3
Câu 5
Cho hàm số \(y = f(x)\) có đồ thị như hình bên. Mệnh đề nào dưới đây đúng?
A.
Hàm số có giá trị cực tiểu bằng 2.
B.
Hàm số có giá trị lớn nhất bằng 2 và giá trị nhỏ nhất bằng -2
C.
Hàm số đạt cực đại tại x = 0 và cực tiểu tại x = 2
D.
Hàm số có ba điểm cực trị.
Câu 6
Hàm số \(% MathType!MTEF!2!1!+-
% feaahqart1ev3aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamyEaiabg2
% da9maabmaabaGaaGinaiabgkHiTiaadIhadaahaaWcbeqaaiaaikda
% aaaakiaawIcacaGLPaaadaahaaWcbeqaaiaaikdaaaGccqGHRaWkca
% aIXaaaaa!3FAB!
y = {\left( {4 - {x^2}} \right)^2} + 1\) có giá trị lớn nhất trên đoạn \([-1; 1]\) là:
A.
10
B.
12
C.
14
D.
17
Câu 7
Tìm tất các các giá trị thực của tham số m để phương trình \(% MathType!MTEF!2!1!+-
% feaahqart1ev3aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamiEamaaCa
% aaleqabaGaaG4maaaakiabgkHiTiaaiodacaWG4bGaey4kaSIaaGOm
% aiaad2gacqGH9aqpcaaIWaaaaa!3EDB!
{x^3} - 3x + 2m = 0\) có ba nghiệm thực phân biệt
A.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamyBaiabgI
% GiopaabmaabaGaeyOeI0IaaGOmaiaacUdacaaIYaaacaGLOaGaayzk
% aaaaaa!3D16!
m \in \left( { - 2;2} \right)\)
B.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamyBaiabgI
% GiopaabmaabaGaeyOeI0IaaGymaiaacUdacaaIXaaacaGLOaGaayzk
% aaaaaa!3D14!
m \in \left( { - 1;1} \right)\)
C.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamyBaiabgI
% GiopaabmaabaGaeyOeI0IaeyOhIuQaai4oaiabgkHiTiaaigdaaiaa
% wIcacaGLPaaacqGHQicYdaqadaqaaiaaigdacaGG7aGaey4kaSIaey
% OhIukacaGLOaGaayzkaaaaaa!45AD!
m\in \left( { - \infty ; - 1} \right) \cup \left( {1; + \infty } \right)\)
D.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamyBaiabgI
% GiopaabmaabaGaeyOeI0IaaGOmaiaacUdacqGHRaWkcqGHEisPaiaa
% wIcacaGLPaaaaaa!3EAD!
m \in \left( { - 2; + \infty } \right)\)
Câu 8
Tìm số hạng không chứa x trong khai triển nhị thức Newton \(% MathType!MTEF!2!1!+-
% feaahqart1ev3aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaWaaeWaaeaaca
% WG4bGaeyOeI0YaaSaaaeaacaaIYaaabaGaamiEamaaCaaaleqabaGa
% aGOmaaaaaaaakiaawIcacaGLPaaadaahaaWcbeqaaiaaikdacaaIXa
% aaaaaa!3DC6!
{\left( {x - \frac{2}{{{x^2}}}} \right)^{21}}\), \(% MathType!MTEF!2!1!+-
% feaahqart1ev3aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaWaaeWaaeaaca
% WG4bGaeyiyIKRaaGimaiaacYcacaaMc8UaaGPaVlaad6gacqGHiiIZ
% cqWIvesPdaahaaWcbeqaaiaacQcaaaaakiaawIcacaGLPaaaaaa!4388!
\left( {x \ne 0,\,\,n \in {N^*}} \right)\).
A.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaaGOmamaaCa
% aaleqabaGaaG4naaaakiaadoeadaqhaaWcbaGaaGOmaiaaigdaaeaa
% caaI3aaaaaaa!3AD4!
{2^7}C_{21}^7\)
B.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaaGOmamaaCa
% aaleqabaGaaGioaaaakiaadoeadaqhaaWcbaGaaGOmaiaaigdaaeaa
% caaI4aaaaaaa!3AD6!
{2^8}C_{21}^8\)
C.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaeyOeI0IaaG
% OmamaaCaaaleqabaGaaGioaaaakiaadoeadaqhaaWcbaGaaGOmaiaa
% igdaaeaacaaI4aaaaaaa!3BC3!
- {2^8}C_{21}^8\)
D.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaeyOeI0IaaG
% OmamaaCaaaleqabaGaaG4naaaakiaadoeadaqhaaWcbaGaaGOmaiaa
% igdaaeaacaaI3aaaaaaa!3BC1!
- {2^7}C_{21}^7\)
Câu 9
Cho hàm số \(% MathType!MTEF!2!1!+-
% feaahqart1ev3aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamyEaiabg2
% da9maabmaabaGaamyBaiabgUcaRiaaigdaaiaawIcacaGLPaaacaWG
% 4bWaaWbaaSqabeaacaaI0aaaaOGaeyOeI0YaaeWaaeaacaWGTbGaey
% OeI0IaaGymaaGaayjkaiaawMcaaiaadIhadaahaaWcbeqaaiaaikda
% aaGccqGHRaWkcaaIXaaaaa!469E!
y = \left( {m + 1} \right){x^4} - \left( {m - 1} \right){x^2} + 1\) . Số các giá trị nguyên của m để hàm số có một điểm cực đại mà không có điểm cực tiểu là:
A.
1
B.
0
C.
3
D.
2
Câu 10
Tập hợp tất cả các giá trị thực của tham số m để đường thẳng \(% MathType!MTEF!2!1!+-
% feaahqart1ev3aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamyEaiabg2
% da9iabgkHiTiaaikdacaWG4bGaey4kaSIaamyBaaaa!3C71!
y = - 2x + m\) cắt đồ thị của hàm số \(% MathType!MTEF!2!1!+-
% feaahqart1ev3aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamyEaiabg2
% da9maalaaabaGaamiEaiabgUcaRiaaigdaaeaacaWG4bGaeyOeI0Ia
% aGOmaaaaaaa!3D47!
y = \frac{{x + 1}}{{x - 2}}\) tại hai điểm phân biệt là.
A.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaWaaeWaaeaacq
% GHsislcqGHEisPcaGG7aGaaGynaiabgkHiTiaaikdadaGcaaqaaiaa
% iAdaaSqabaaakiaawIcacaGLPaaacqGHQicYdaqadaqaaiaaiwdacq
% GHRaWkcaaIYaWaaOaaaeaacaaI2aaaleqaaOGaai4oaiabgUcaRiab
% g6HiLcGaayjkaiaawMcaaaaa!4763!
\left( { - \infty ;5 - 2\sqrt 6 } \right) \cup \left( {5 + 2\sqrt 6 ; + \infty } \right)\)
B.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaWaaKamaeaacq
% GHsislcqGHEisPcaGG7aGaaGynaiabgkHiTiaaikdadaGcaaqaaiaa
% iAdaaSqabaaakiaawIcacaGLDbaacqGHQicYdaqcsaqaaiaaiwdacq
% GHRaWkcaaIYaWaaOaaaeaacaaI2aaaleqaaOGaai4oaiabgUcaRiab
% g6HiLcGaay5waiaawMcaaaaa!4816!
\left( { - \infty ;5 - 2\sqrt 6 } \right] \cup \left[ {5 + 2\sqrt 6 ; + \infty } \right)\)
C.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaWaaeWaaeaaca
% aI1aGaeyOeI0IaaGOmamaakaaabaGaaG4maaWcbeaakiaacUdacaaI
% 1aGaey4kaSIaaGOmamaakaaabaGaaG4maaWcbeaaaOGaayjkaiaawM
% caaaaa!3EC4!
\left( {5 - 2\sqrt 3 ;5 + 2\sqrt 3 } \right)\)
D.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaWaaeWaaeaacq
% GHsislcqGHEisPcaGG7aGaaGynaiabgkHiTiaaikdadaGcaaqaaiaa
% iodaaSqabaaakiaawIcacaGLPaaacqGHQicYdaqadaqaaiaaiwdacq
% GHRaWkcaaIYaWaaOaaaeaacaaIZaaaleqaaOGaai4oaiabgUcaRiab
% g6HiLcGaayjkaiaawMcaaaaa!475D!
\left( { - \infty ;5 - 2\sqrt 3 } \right) \cup \left( {5 + 2\sqrt 3 ; + \infty } \right)\)
Câu 11
Cho hàm số \(% MathType!MTEF!2!1!+-
% feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamOzamaabm
% aabaGaamiEaaGaayjkaiaawMcaaiabg2da9iaadIhadaahaaWcbeqa
% aiaaiodaaaGccqGHsislcaaIZaGaamiEamaaCaaaleqabaGaaGOmaa
% aakiabgUcaRiaaikdaaaa!4194!
f\left( x \right) = {x^3} - 3{x^2} + 2\) có đồ thị là đường cong trong hình bên.
A.
7
B.
9
C.
6
D.
5
Câu 12
Tìm tất cả các giá trị thực của tham số m để đồ thị hàm số \(% MathType!MTEF!2!1!+-
% feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamyEaiabg2
% da9maalaaabaGaamiEaiabgUcaRiaaigdaaeaadaGcaaqaaiaad2ga
% daqadaqaaiaadIhacqGHsislcaaIXaaacaGLOaGaayzkaaWaaWbaaS
% qabeaacaaIYaaaaOGaey4kaSIaaGinaaWcbeaaaaaaaa!4270!
y = \frac{{x + 1}}{{\sqrt {m{{\left( {x - 1} \right)}^2} + 4} }}\) có hai tiệm cận đứng:
A.
m < 0
B.
m = 0
C.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaWaaiqaaqaabe
% qaaiaad2gacqGH8aapcaaIWaaabaGaamyBaiabgcMi5kabgkHiTiaa
% igdaaaGaay5EaaGaaiOlaaaa!3ED8!
\left\{ \begin{array}{l}
m < 0\\
m \ne - 1
\end{array} \right..\)
D.
m < 1
Câu 13
Đồ thị hàm số nào sau đây nằm phía dưới trục hoành?
A.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamyEaiabg2
% da9iaadIhadaahaaWcbeqaaiaaisdaaaGccqGHRaWkcaaI1aGaamiE
% amaaCaaaleqabaGaaGOmaaaakiabgkHiTiaaigdacaGGUaaaaa!3FD4!
y = {x^4} + 5{x^2} - 1.\)
B.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamyEaiabg2
% da9iabgkHiTiaadIhadaahaaWcbeqaaiaaiodaaaGccqGHsislcaaI
% 3aGaamiEamaaCaaaleqabaGaaGOmaaaakiabgkHiTiaadIhacqGHsi
% slcaaIXaGaaiOlaaaa!42B7!
y = - {x^3} - 7{x^2} - x - 1.\)
C.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamyEaiabg2
% da9iabgkHiTiaadIhadaahaaWcbeqaaiaaisdaaaGccqGHRaWkcaaI
% YaGaamiEamaaCaaaleqabaGaaGOmaaaakiabgkHiTiaaikdacaGGUa
% aaaa!40BF!
y = - {x^4} + 2{x^2} - 2.\)
D.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamyEaiabg2
% da9iabgkHiTiaadIhadaahaaWcbeqaaiaaisdaaaGccqGHsislcaaI
% 0aGaamiEamaaCaaaleqabaGaaGOmaaaakiabgUcaRiaaigdacaGGUa
% aaaa!40C0!
y = - {x^4} - 4{x^2} + 1.\)
Câu 14
Cho hàm số \(% MathType!MTEF!2!1!+-
% feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamyEaiabg2
% da9iaadggacaWG4bWaaWbaaSqabeaacaaI0aaaaOGaey4kaSIaamOy
% aiaadIhadaahaaWcbeqaaiaaikdaaaGccqGHRaWkcaWGJbaaaa!4053!
y = a{x^4} + b{x^2} + c\) có đồ thị như hình bên.
A.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamyyaiabg6
% da+iaaicdacaGGSaGaamOyaiabgYda8iaaicdacaGGSaGaam4yaiab
% g6da+iaaicdacaGGUaaaaa!3FFD!
a > 0,b < 0,c > 0.\)
B.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamyyaiabg6
% da+iaaicdacaGGSaGaamOyaiabgYda8iaaicdacaGGSaGaam4yaiab
% gYda8iaaicdacaGGUaaaaa!3FF9!
a > 0,b < 0,c < 0.\)
C.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamyyaiabg6
% da+iaaicdacaGGSaGaamOyaiabg6da+iaaicdacaGGSaGaam4yaiab
% gYda8iaaicdacaGGUaaaaa!3FFD!
a > 0,b > 0,c < 0.\)
D.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamyyaiabgY
% da8iaaicdacaGGSaGaamOyaiabg6da+iaaicdacaGGSaGaam4yaiab
% gYda8iaaicdacaGGUaaaaa!3FF9!
a < 0,b > 0,c < 0.\)
Câu 15
Hàm số nào trong bốn hàm số sau có bảng biến thiên như hình vẽ sau?
A.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamyEaiabg2
% da9iabgkHiTiaadIhadaahaaWcbeqaaiaaiodaaaGccqGHRaWkcaaI
% ZaGaamiEamaaCaaaleqabaGaaGOmaaaakiabgkHiTiaaigdacaGGUa
% aaaa!40BF!
y = - {x^3} + 3{x^2} - 1.\)
B.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamyEaiabg2
% da9iaadIhadaahaaWcbeqaaiaaiodaaaGccqGHRaWkcaaIZaGaamiE
% amaaCaaaleqabaGaaGOmaaaakiabgkHiTiaaigdacaGGUaaaaa!3FD2!
y = {x^3} + 3{x^2} - 1.\)
C.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamyEaiabg2
% da9iaadIhadaahaaWcbeqaaiaaiodaaaGccqGHsislcaaIZaGaamiE
% aiabgUcaRiaaikdacaGGUaaaaa!3EE0!
y = {x^3} - 3x + 2.\)
D.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamyEaiabg2
% da9iaadIhadaahaaWcbeqaaiaaiodaaaGccqGHsislcaaIZaGaamiE
% amaaCaaaleqabaGaaGOmaaaakiabgUcaRiaaikdacaGGUaaaaa!3FD3!
y = {x^3} - 3{x^2} + 2.\)
Câu 16
Cho hàm số \(y = f(x)\) có đạo hàm trên R . Đường cong trong hình vẽ bên là đồ thị hàm số \(y = f'(x)\) , ( \(y = f'(x)\) liên tục trên R ). Xét hàm số .png)
A.
Hàm số \(g(x)\) nghịch biến trên khoảng \(% MathType!MTEF!2!1!+-
% feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaWaaeWaaeaacq
% GHsislcqGHEisPcaGG7aGaaGPaVlabgkHiTiaaikdaaiaawIcacaGL
% Paaaaaa!3DCE!
\left( { - \infty ;\, - 2} \right)\).
B.
Hàm số \(g(x)\) đồng biến trên khoảng \(% MathType!MTEF!2!1!+-
% feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaWaaeWaaeaaca
% aIYaGaai4oaiaaykW7cqGHRaWkcqGHEisPaiaawIcacaGLPaaaaaa!3CD6!
\left( {2;\, + \infty } \right)\).
C.
Hàm số \(g(x)\) nghịch biến trên khoảng ( - 1;0) .
D.
Hàm số \(g(x)\) nghịch biến trên khoảng (0;2).
Câu 17
Cho các số thực dương a,b với \(a\ne0\) và \(% MathType!MTEF!2!1!+-
% feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaciiBaiaac+
% gacaGGNbWaaSbaaSqaaiaadggaaeqaaOGaamOyaiabg6da+iaaicda
% aaa!3C89!
{\log _a}b > 0\) . Khẳng định nào sau đây là đúng?
A.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaWaamqaaqaabe
% qaaiaaicdacqGH8aapcaWGHbGaaiilaiaaykW7caWGIbGaeyipaWJa
% aGymaaqaaiaaicdacqGH8aapcaWGHbGaeyipaWJaaGymaiabgYda8i
% aadkgaaaGaay5waaaaaa!44C9!
\left[ \begin{array}{l}
0 < a,\,b < 1\\
0 < a < 1 < b
\end{array} \right.\)
B.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaWaamqaaqaabe
% qaaiaaicdacqGH8aapcaWGHbGaaiilaiaaykW7caWGIbGaeyipaWJa
% aGymaaqaaiaaigdacqGH8aapcaWGHbGaaiilaiaaykW7caaMc8Uaam
% OyaaaacaGLBbaaaaa!45CD!
\left[ \begin{array}{l}
0 < a,\,b < 1\\
1 < a,\,\,b
\end{array} \right.\)
C.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaWaamqaaqaabe
% qaaiaaicdacqGH8aapcaWGIbGaeyipaWJaaGymaiabgYda8iaadgga
% aeaacaaIXaGaeyipaWJaamyyaiaacYcacaaMc8UaaGPaVlaadkgaaa
% Gaay5waaaaaa!4496!
\left[ \begin{array}{l}
0 < b < 1 < a\\
1 < a,\,\,b
\end{array} \right.\)
D.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaWaamqaaqaabe
% qaaiaaicdacqGH8aapcaWGHbGaaiilaiaaykW7caWGIbGaeyipaWJa
% aGymaaqaaiaaicdacqGH8aapcaWGIbGaeyipaWJaaGymaiabgYda8i
% aadggaaaGaay5waaaaaa!44C9!
\left[ \begin{array}{l}
0 < a,\,b < 1\\
0 < b < 1 < a
\end{array} \right.\)
Câu 18
Tính tích tất cả các nghiệm thực của phương trình \(% MathType!MTEF!2!1!+-
% feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaciiBaiaac+
% gacaGGNbWaaSbaaSqaaiaaikdaaeqaaOWaaeWaaeaadaWcaaqaaiaa
% ikdacaWG4bWaaWbaaSqabeaacaaIYaaaaOGaey4kaSIaaGymaaqaai
% aaikdacaWG4baaaaGaayjkaiaawMcaaiabgUcaRiaaikdadaahaaWc
% beqaamaabmaabaGaamiEaiabgUcaRmaalaaabaGaaGymaaqaaiaaik
% dacaWG4baaaaGaayjkaiaawMcaaaaakiabg2da9iaaiwdaaaa!4AD7!
{\log _2}\left( {\frac{{2{x^2} + 1}}{{2x}}} \right) + {2^{\left( {x + \frac{1}{{2x}}} \right)}} = 5\)
A.
0
B.
2
C.
1
D.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaWaaSaaaeaaca
% aIXaaabaGaaGOmaaaaaaa!377B!
\frac{1}{2}\)
Câu 19
Tập xác định của hàm số \(% MathType!MTEF!2!1!+-
% feaahqart1ev3aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamyEaiabg2
% da9maabmaabaGaamiEaiabgkHiTiaaigdaaiaawIcacaGLPaaadaah
% aaWcbeqaamaalaaabaGaaGymaaqaaiaaiwdaaaaaaaaa!3DDC!
y = {\left( {x - 1} \right)^{\frac{1}{5}}}\) là:
A.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaWaaeWaaeaaca
% aIWaGaai4oaiaaykW7cqGHRaWkcqGHEisPaiaawIcacaGLPaaaaaa!3CD4!
\left( {0;\, + \infty } \right)\)
B.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaWaaKGeaeaaca
% aIXaGaai4oaiaaykW7cqGHRaWkcqGHEisPaiaawUfacaGLPaaaaaa!3D1F!
\left[ {1;\, + \infty } \right)\)
C.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaWaaeWaaeaaca
% aIXaGaai4oaiaaykW7cqGHRaWkcqGHEisPaiaawIcacaGLPaaaaaa!3CD5!
\left( {1;\, + \infty } \right)\)
D.
R
Câu 20
Tổng \(% MathType!MTEF!2!1!+-
% feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamivaiabg2
% da9iaadoeadaqhaaWcbaGaaGOmaiaaicdacaaIXaGaaG4naaqaaiaa
% igdaaaGccqGHRaWkcaWGdbWaa0baaSqaaiaaikdacaaIWaGaaGymai
% aaiEdaaeaacaaIZaaaaOGaey4kaSIaam4qamaaDaaaleaacaaIYaGa
% aGimaiaaigdacaaI3aaabaGaaGynaaaakiabgUcaRiaac6cacaGGUa
% GaaiOlaiabgUcaRiaadoeadaqhaaWcbaGaaGOmaiaaicdacaaIXaGa
% aG4naaqaaiaaikdacaaIWaGaaGymaiaaiEdaaaaaaa!5254!
T = C_{2017}^1 + C_{2017}^3 + C_{2017}^5 + ... + C_{2017}^{2017}\) bằng:
A.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaaGOmamaaCa
% aaleqabaGaaGOmaiaaicdacaaIXaGaaG4naaaakiabgkHiTiaaigda
% aaa!3B81!
{2^{2017}} - 1\)
B.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaaGOmamaaCa
% aaleqabaGaaGOmaiaaicdacaaIXaGaaGOnaaaaaaa!39CE!
{2^{2016}}\)
C.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaaGOmamaaCa
% aaleqabaGaaGOmaiaaicdacaaIXaGaaG4naaaaaaa!39CF!
{2^{2017}}\)
D.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaaGOmamaaCa
% aaleqabaGaaGOmaiaaicdacaaIXaGaaGOnaaaakiabgkHiTiaaigda
% aaa!3B80!
{2^{2016}} - 1\)
Câu 21
Trong các hàm số dưới đây, hàm số nào nghịch biến trên tập số thực R ?
A.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamyEaiabg2
% da9maabmaabaWaaSaaaeaacqaHapaCaeaacaaIZaaaaaGaayjkaiaa
% wMcaamaaCaaaleqabaGaamiEaaaaaaa!3D35!
y = {\left( {\frac{\pi }{3}} \right)^x}\)
B.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamyEaiabg2
% da9iGacYgacaGGVbGaai4zamaaBaaaleaadaWcaaqaaiaaigdaaeaa
% caaIYaaaaaqabaGccaWG4baaaa!3D82!
y = {\log _{\frac{1}{2}}}x\)
C.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamyEaiabg2
% da9iGacYgacaGGVbGaai4zamaaBaaaleaadaWcaaqaaiabec8aWbqa
% aiaaisdaaaaabeaakmaabmaabaGaaGOmaiaadIhadaahaaWcbeqaai
% aaikdaaaGccqGHRaWkcaaIXaaacaGLOaGaayzkaaaaaa!435B!
y = {\log _{\frac{\pi }{4}}}\left( {2{x^2} + 1} \right)\)
D.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamyEaiabg2
% da9maabmaabaWaaSaaaeaacaaIYaaabaGaamyzaaaaaiaawIcacaGL
% PaaadaahaaWcbeqaaiaadIhaaaaaaa!3C61!
y = {\left( {\frac{2}{e}} \right)^x}\)
Câu 22
Một hình trụ có bán kính đáy r = 5cm và khoảng cách giữa hai đáy h = 7cm . Cắt khối trụ bởi một mặt phẳng song song với trục và cách trục 3cm. Diện tích của thiết diện được tạo thành là:
A.
\(S = 56 ( cm^2)\)
B.
\(S=55(cm^2)\)
C.
\(S= 53(cm^2)\)
D.
\(S=46(cm^2)\)
Câu 23
Một tấm kẽm hình vuông ABCD có cạnh bằng 30cm . Người ta gập tấm kẽm theo hai cạnh EF và GH cho đến khi AD và BC trùng nhau như hình vẽ bên để được một hình lăng trụ khuyết hai đáy.
A.
x= 5(cm)
B.
x= 9(cm)
C.
x= 8(cm)
D.
x= 10(cm)
Câu 24
Độ giảm huyết áp của một bệnh nhân được cho bởi công thức \(% MathType!MTEF!2!1!+-
% feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaam4ramaabm
% aabaGaamiEaaGaayjkaiaawMcaaiabg2da9iaaicdacaGGSaGaaGim
% aiaaiodacaaI1aGaamiEamaaCaaaleqabaGaaGOmaaaakmaabmaaba
% GaaGymaiaaiwdacqGHsislcaWG4baacaGLOaGaayzkaaaaaa!44C9!
G\left( x \right) = 0,035{x^2}\left( {15 - x} \right)\) , trong đó x là liều lượng thuốc được tiêm cho bệnh nhân ( x được tính bằng miligam). Tính liều lượng thuốc cần tiêm (đơn vị miligam) cho bệnh nhân để huyết áp giảm nhiều nhất.
A.
8
B.
10
C.
15
D.
7
Câu 25
Đặt \(% MathType!MTEF!2!1!+-
% feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaciiBaiaac6
% gacaaIYaGaeyypa0Jaamyyaaaa!3A80!
\ln 2 = a\), \(% MathType!MTEF!2!1!+-
% feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaciiBaiaac+
% gacaGGNbWaaSbaaSqaaiaaiwdaaeqaaOGaaGinaiabg2da9iaadkga
% aaa!3C64!
{\log _5}4 = b\). Mệnh đề nào dưới đây là đúng?
A.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaciiBaiaac6
% gacaaIXaGaaGimaiaaicdacqGH9aqpdaWcaaqaaiaadggacaWGIbGa
% ey4kaSIaaGOmaiaadggaaeaacaWGIbaaaaaa!4055!
\ln 100 = \frac{{ab + 2a}}{b}\)
B.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaciiBaiaac6
% gacaaIXaGaaGimaiaaicdacqGH9aqpdaWcaaqaaiaaisdacaWGHbGa
% amOyaiabgUcaRiaaikdacaWGHbaabaGaamOyaaaaaaa!4113!
\ln 100 = \frac{{4ab + 2a}}{b}\)
C.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaciiBaiaac6
% gacaaIXaGaaGimaiaaicdacqGH9aqpdaWcaaqaaiaadggacaWGIbGa
% ey4kaSIaamyyaaqaaiaadkgaaaaaaa!3F99!
\ln 100 = \frac{{ab + a}}{b}\)
D.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaciiBaiaac6
% gacaaIXaGaaGimaiaaicdacqGH9aqpdaWcaaqaaiaaikdacaWGHbGa
% amOyaiabgUcaRiaaisdacaWGHbaabaGaamOyaaaaaaa!4113!
\ln 100 = \frac{{2ab + 4a}}{b}\)
Câu 26
Số nghiệm thực của phương trình \(% MathType!MTEF!2!1!+-
% feaahqart1ev3aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaaGinamaaCa
% aaleqabaGaamiEaaaakiabgkHiTiaaikdadaahaaWcbeqaaiaadIha
% cqGHRaWkcaaIYaaaaOGaey4kaSIaaG4maiabg2da9iaaicdaaaa!3FBF!
{4^x} - {2^{x + 2}} + 3 = 0\) là:
A.
0
B.
1
C.
2
D.
3
Câu 27
Từ các chữ số 1,2,3,4,5,6 có thể lập được bao nhiêu số tự nhiên gồm 4 chữ số đôi một khác nhau?
A.
15
B.
4096
C.
360
D.
720
Câu 28
Cho hình chóp tam giác đều có cạnh đáy bằng \(% MathType!MTEF!2!1!+-
% feaahqart1ev3aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaWaaOaaaeaaca
% aI2aaaleqaaaaa!36CE!
\sqrt 6 \) và chiều cao h = 1. Diện tích của mặt cầu ngoại tiếp của hình chóp đó là:
A.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaam4uaiabg2
% da9iaaiMdacqaHapaCaaa!3A51!
S = 9\pi \)
B.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaam4uaiabg2
% da9iaaiAdacqaHapaCaaa!3A4E!
S = 6\pi \)
C.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaam4uaiabg2
% da9iaaiwdacqaHapaCaaa!3A4D!
S = 5\pi\)
D.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaam4uaiabg2
% da9iaaikdacaaI3aGaeqiWdahaaa!3B0B!
S = 27\pi \)
Câu 29
Biết rằng hệ số của \(x^4\) trong khai triển nhị thức Newton \(% MathType!MTEF!2!1!+-
% feaahqart1ev3aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaWaaeWaaeaaca
% aIYaGaeyOeI0IaamiEaaGaayjkaiaawMcaamaaCaaaleqabaGaamOB
% aaaakiaacYcacaaMc8+aaeWaaeaacaWGUbGaeyicI4SaeSyfHu6aaW
% baaSqabeaacaGGQaaaaaGccaGLOaGaayzkaaaaaa!43D8!
{\left( {2 - x} \right)^n},\,\left( {n \in {N^*}} \right)\) bằng 60 Tìm n.
A.
n = 5
B.
n= 6
C.
n= 7
D.
n= 8
Câu 30
Cho hình lăng trụ đứng ABC.A'B'C' có đáy là tam giác ABC vuông tại A có BC = 2a, \(% MathType!MTEF!2!1!+-
% feaahqart1ev3aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamyqaiaadk
% eacqGH9aqpcaWGHbWaaOaaaeaacaaIZaaaleqaaaaa!3A44!
AB = a\sqrt 3 \) . Khoảng cách từ (AA') đến mặt phẳng (BCC'B') là:
A.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaWaaSaaaeaaca
% WGHbWaaOaaaeaacaaIYaGaaGymaaWcbeaaaOqaaiaaiEdaaaaaaa!3946!
\frac{{a\sqrt {21} }}{7}\)
B.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaWaaSaaaeaaca
% WGHbWaaOaaaeaacaaIZaaaleqaaaGcbaGaaGOmaaaaaaa!3887!
\frac{{a\sqrt 3 }}{2}\)
C.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaWaaSaaaeaaca
% WGHbWaaOaaaeaacaaI1aaaleqaaaGcbaGaaGOmaaaaaaa!3889!
\frac{{a\sqrt 5 }}{2}\)
D.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaWaaSaaaeaaca
% WGHbWaaOaaaeaacaaI3aaaleqaaaGcbaGaaG4maaaaaaa!388C!
\frac{{a\sqrt 7 }}{3}\)
Câu 31
Cho tập A gồm n điểm phân biệt trên mặt phẳng sao cho không có 3 điểm nào thẳng hàng. Tìm n sao cho số tam giác có 3 đỉnh lấy từ 3 điểm thuộc A gấp đôi số đoạn thẳng được nối từ 2 điểm thuộc A .
A.
n= 6
B.
n= 12
C.
n= 8
D.
n= 15
Câu 32
Cho hàm số \(% MathType!MTEF!2!1!+-
% feaahqart1ev3aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamyEaiabg2
% da9iGacYgacaGGUbWaaeWaaeaacaWGLbWaaWbaaSqabeaacaWG4baa
% aOGaey4kaSIaamyBamaaCaaaleqabaGaaGOmaaaaaOGaayjkaiaawM
% caaaaa!4049!
y = \ln \left( {{e^x} + {m^2}} \right)\). Với giá trị nào của m thì \(% MathType!MTEF!2!1!+-
% feaahqart1ev3aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGabmyEayaafa
% WaaeWaaeaacaaIXaaacaGLOaGaayzkaaGaeyypa0ZaaSaaaeaacaaI
% XaaabaGaaGOmaaaaaaa!3BCE!
y'\left( 1 \right) = \frac{1}{2}\)
A.
m = e
B.
m = - e
C.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamyBaiabg2
% da9maalaaabaGaaGymaaqaaiaadwgaaaGaaiOlaaaa!3A52!
m = \frac{1}{e}.\)
D.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamyBaiabg2
% da9iabgglaXoaakaaabaGaamyzaaWcbeaakiaac6caaaa!3B9A!
m = \pm \sqrt e .\)
Câu 33
Cho hàm \(% MathType!MTEF!2!1!+-
% feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamyEaiabg2
% da9maakaaabaGaamiEamaaCaaaleqabaGaaGOmaaaakiabgkHiTiaa
% iAdacaWG4bGaey4kaSIaaGynaaWcbeaaaaa!3E4E!
y = \sqrt {{x^2} - 6x + 5} \). Mệnh đề nào sau đây là đúng?
A.
Hàm số đồng biến trên khoảng \(% MathType!MTEF!2!1!+-
% feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaWaaeWaaeaaca
% aI1aGaai4oaiabgUcaRiabg6HiLcGaayjkaiaawMcaaiaac6caaaa!3C00!
\left( {5; + \infty } \right).\)
B.
Hàm số đồng biến trên khoảng \(% MathType!MTEF!2!1!+-
% feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaWaaeWaaeaaca
% aIZaGaai4oaiabgUcaRiabg6HiLcGaayjkaiaawMcaaiaac6caaaa!3BFE!
\left( {3; + \infty } \right).\)
C.
Hàm số đồng biến trên khoảng \(% MathType!MTEF!2!1!+-
% feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaWaaeWaaeaacq
% GHsislcqGHEisPcaGG7aGaaGymaaGaayjkaiaawMcaaiaac6caaaa!3C07!
\left( { - \infty ;1} \right).\)
D.
Hàm số nghịch biến trên khoảng \(% MathType!MTEF!2!1!+-
% feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaWaaeWaaeaacq
% GHsislcqGHEisPcaGG7aGaaG4maaGaayjkaiaawMcaaiaac6caaaa!3C09!
\left( { - \infty ;3} \right).\)
Câu 34
Một lớp có 20 nam sinh và 15 nữ sinh. Giáo viên chọn ngẫu nhiên 4 học sinh lên bảng giải bài tập. Tính xác suất để 4 học sinh được chọn có cả nam và nữ.
A.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaWaaSaaaeaaca
% aI0aGaaGOnaiaaigdacaaI1aaabaGaaGynaiaaikdacaaIZaGaaGOn
% aaaacaGGUaaaaa!3CA6!
\frac{{4615}}{{5236}}.\)
B.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaWaaSaaaeaaca
% aI0aGaaGOnaiaaiwdacaaIXaaabaGaaGynaiaaikdacaaIZaGaaGOn
% aaaacaGGUaaaaa!3CA6!
\frac{{4651}}{{5236}}.\)
C.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaWaaSaaaeaaca
% aI0aGaaGOnaiaaigdacaaI1aaabaGaaGynaiaaikdacaaI2aGaaG4m
% aaaacaGGUaaaaa!3CA6!
\frac{{4615}}{{5263}}.\)
D.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaWaaSaaaeaaca
% aI0aGaaGOnaiaaigdacaaIWaaabaGaaGynaiaaikdacaaIZaGaaGOn
% aaaacaGGUaaaaa!3CA1!
\frac{{4610}}{{5236}}.\)
Câu 35
Một đề thi trắc nghiệm gồm 50 câu, mỗi câu có 4 phương án trả lời trong đó chỉ có 1 phương án đúng, mỗi câu trả lời đúng được 0,2 điểm. Một thí sinh làm bài bằng cách chọn ngẫu nhiên 1 trong 4 phương án ở mỗi câu. Tính xác suất để thí sinh đó được 6 điểm.
A.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaaGimaiaacY
% cacaaIYaGaaGynamaaCaaaleqabaGaaG4maiaaicdaaaGccaGGUaGa
% aGimaiaacYcacaaI3aGaaGynamaaCaaaleqabaGaaGOmaiaaicdaaa
% GccaGGUaaaaa!4082!
0,{25^{30}}.0,{75^{20}}.\)
B.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaaGimaiaacY
% cacaaIYaGaaGynamaaCaaaleqabaGaaGOmaiaaicdaaaGccaGGUaGa
% aGimaiaacYcacaaI3aGaaGynamaaCaaaleqabaGaaG4maiaaicdaaa
% GccaGGUaaaaa!4082!
0,{25^{20}}.0,{75^{30}}.\)
C.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaaGimaiaacY
% cacaaIYaGaaGynamaaCaaaleqabaGaaG4maiaaicdaaaGccaGGUaGa
% aGimaiaacYcacaaI3aGaaGynamaaCaaaleqabaGaaGOmaiaaicdaaa
% GccaGGUaGaam4qamaaDaaaleaacaaI1aGaaGimaaqaaiaaikdacaaI
% WaaaaOGaaiOlaaaa!4522!
0,{25^{30}}.0,{75^{20}}.C_{50}^{20}.\)
D.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaaGymaiabgk
% HiTiaaicdacaGGSaGaaGOmaiaaiwdadaahaaWcbeqaaiaaikdacaaI
% WaaaaOGaaiOlaiaaicdacaGGSaGaaG4naiaaiwdadaahaaWcbeqaai
% aaiodacaaIWaaaaOGaaiOlaaaa!422A!
1 - 0,{25^{20}}.0,{75^{30}}.\)
Câu 36
Cho hàm số \(% MathType!MTEF!2!1!+-
% feaahqart1ev3aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamyEaiabg2
% da9maalaaabaGaaGOmaiaaicdacaaIXaGaaG4naaqaaiaadIhacqGH
% sislcaaIYaaaaaaa!3D9F!
y = \frac{{2017}}{{x - 2}}\) có đồ thị (H). Số đường tiệm cận của (H) là?
A.
0
B.
2
C.
3
D.
1
Câu 37
Một khối lăng trụ tam giác có đáy là tam giác đều cạnh 3, cạnh bên bằng \(% MathType!MTEF!2!1!+-
% feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaaGOmamaaka
% aabaGaaG4maaWcbeaaaaa!3788!
2\sqrt 3 \) và tạo với mặt phẳng đáy một góc \(% MathType!MTEF!2!1!+-
% feaahqart1ev3aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaaG4maiaaic
% dacqGHWcaScaGGUaaaaa!3A08!
30^\circ .\) Khi đó thể tích khối lăng trụ là?
A.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaWaaSaaaeaaca
% aI5aaabaGaaGinaaaacaGGUaaaaa!3836!
\frac{9}{4}.\)
B.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaWaaSaaaeaaca
% aIYaGaaG4namaakaaabaGaaG4maaWcbeaaaOqaaiaaisdaaaGaaiOl
% aaaa!39D2!
\frac{{27\sqrt 3 }}{4}.\)
C.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaWaaSaaaeaaca
% aIYaGaaG4naaqaaiaaisdaaaGaaiOlaaaa!38F0!
\frac{{27}}{4}.\)
D.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaWaaSaaaeaaca
% aI5aWaaOaaaeaacaaIZaaaleqaaaGcbaGaaGinaaaacaGGUaaaaa!3918!
\frac{{9\sqrt 3 }}{4}.\)
Câu 38
Cho hình chóp S.ABCD có SA vuông góc với mặt phẳng (ABCD) đáy ABCD là hình thang vuông tại A và B có \(% MathType!MTEF!2!1!+-
% feaahqart1ev3aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamyqaiaadk
% eacqGH9aqpcaWGHbGaaiilaiaabccacaWGbbGaamiraiabg2da9iaa
% iodacaWGHbGaaiilaiaabccacaWGcbGaam4qaiabg2da9iaadggaca
% GGUaaaaa!4477!
AB = a,{\rm{ }}AD = 3a,{\rm{ }}BC = a.\) Biết \(% MathType!MTEF!2!1!+-
% feaahqart1ev3aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaam4uaiaadg
% eacqGH9aqpcaWGHbWaaOaaaeaacaaIZaaaleqaaOGaaiilaaaa!3B0F!
SA = a\sqrt 3 ,\) tính thể tích khối chóp S.BCD theo a
A.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaaGOmamaaka
% aabaGaaG4maaWcbeaakiaadggadaahaaWcbeqaaiaaiodaaaGccaGG
% Uaaaaa!3A1E!
2\sqrt 3 {a^3}.\)
B.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaWaaSaaaeaada
% GcaaqaaiaaiodaaSqabaGccaWGHbWaaWbaaSqabeaacaaIZaaaaaGc
% baGaaGOnaaaacaGGUaaaaa!3A32!
\frac{{\sqrt 3 {a^3}}}{6}.\)
C.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaWaaSaaaeaaca
% aIYaWaaOaaaeaacaaIZaaaleqaaOGaamyyamaaCaaaleqabaGaaG4m
% aaaaaOqaaiaaiodaaaGaaiOlaaaa!3AEB!
\frac{{2\sqrt 3 {a^3}}}{3}.\)
D.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaWaaSaaaeaada
% GcaaqaaiaaiodaaSqabaGccaWGHbWaaWbaaSqabeaacaaIZaaaaaGc
% baGaaGinaaaacaGGUaaaaa!3A30!
\frac{{\sqrt 3 {a^3}}}{4}.\)
Câu 39
Cho hình nón có góc ở đỉnh bằng \(% MathType!MTEF!2!1!+-
% feaahqart1ev3aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaaGOnaiaaic
% dacqGHWcaScaGGSaaaaa!3A09!
60^\circ ,\) diện tích xung quanh bằng \(% MathType!MTEF!2!1!+-
% feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaaGOnaiabec
% 8aWjaadggadaahaaWcbeqaaiaaikdaaaaaaa!3A40!
6\pi {a^2}\). Tính thể tích của khối nón đã cho.
A.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamOvaiabg2
% da9maalaaabaGaaG4maiabec8aWjaadggadaahaaWcbeqaaiaaioda
% aaGcdaGcaaqaaiaaikdaaSqabaaakeaacaaI0aaaaaaa!3DD8!
V = \frac{{3\pi {a^3}\sqrt 2 }}{4}\)
B.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamOvaiabg2
% da9maalaaabaGaeqiWdaNaamyyamaaCaaaleqabaGaaG4maaaakmaa
% kaaabaGaaGOmaaWcbeaaaOqaaiaaisdaaaaaaa!3D1B!
V = \frac{{\pi {a^3}\sqrt 2 }}{4}\)
C.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamOvaiabg2
% da9iaaiodacqaHapaCcaWGHbWaaWbaaSqabeaacaaIZaaaaaaa!3C1F!
V = 3\pi {a^3}\)
D.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamOvaiabg2
% da9iabec8aWjaadggadaahaaWcbeqaaiaaiodaaaaaaa!3B62!
V = \pi {a^3}\)
Câu 40
Cho hình hộp ABCD.A'B'C'D' thể tích là V Tính thể tích của tứ diện ACB'D' theo V
A.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaWaaSaaaeaaca
% WGwbaabaGaaGOnaaaacaGGUaaaaa!3851!
\frac{V}{6}.\)
B.
\(\frac{V}{4}\)
C.
\(\frac{V}{5}\)
D.
\(\frac{V}{3}\)
Câu 41
Cho lăng trụ tam giác đều có cạnh đáy bằng a cạnh bên bằng b. Tính thể tích của khối cầu đi qua các đỉnh của lăng trụ.
A.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaWaaSaaaeaaca
% aIXaaabaGaaGymaiaaiIdadaGcaaqaaiaaiodaaSqabaaaaOWaaOaa
% aeaadaqadaqaaiaaisdacaWGHbWaaWbaaSqabeaacaaIYaaaaOGaey
% 4kaSIaaG4maiaadkgadaahaaWcbeqaaiaaikdaaaaakiaawIcacaGL
% PaaadaahaaWcbeqaaiaaiodaaaaabeaakiaac6caaaa!426D!
\frac{1}{{18\sqrt 3 }}\sqrt {{{\left( {4{a^2} + 3{b^2}} \right)}^3}} .\)
B.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaWaaSaaaeaacq
% aHapaCaeaacaaIXaGaaGioamaakaaabaGaaG4maaWcbeaaaaGcdaGc
% aaqaamaabmaabaGaaGinaiaadggadaahaaWcbeqaaiaaikdaaaGccq
% GHRaWkcaaIZaGaamOyamaaCaaaleqabaGaaGOmaaaaaOGaayjkaiaa
% wMcaamaaCaaaleqabaGaaG4maaaaaeqaaOGaaiOlaaaa!436F!
\frac{\pi }{{18\sqrt 3 }}\sqrt {{{\left( {4{a^2} + 3{b^2}} \right)}^3}} .\)
C.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaWaaSaaaeaacq
% aHapaCaeaacaaIXaGaaGioamaakaaabaGaaG4maaWcbeaaaaGcdaGc
% aaqaamaabmaabaGaaGinaiaadggadaahaaWcbeqaaiaaikdaaaGccq
% GHRaWkcaWGIbWaaWbaaSqabeaacaaIYaaaaaGccaGLOaGaayzkaaWa
% aWbaaSqabeaacaaIZaaaaaqabaGccaGGUaaaaa!42B2!
\frac{\pi }{{18\sqrt 3 }}\sqrt {{{\left( {4{a^2} + {b^2}} \right)}^3}} \)
D.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaWaaSaaaeaacq
% aHapaCaeaacaaIXaGaaGioamaakaaabaGaaGOmaaWcbeaaaaGcdaGc
% aaqaamaabmaabaGaaGinaiaadggadaahaaWcbeqaaiaaikdaaaGccq
% GHRaWkcaaIZaGaamOyamaaCaaaleqabaGaaGOmaaaaaOGaayjkaiaa
% wMcaamaaCaaaleqabaGaaG4maaaaaeqaaOGaaiOlaaaa!436E!
\frac{\pi }{{18\sqrt 2 }}\sqrt {{{\left( {4{a^2} + 3{b^2}} \right)}^3}} \)
Câu 42
Cho hình trụ có thiết diện qua trục là hình vuông ABCD cạnh bằng \(% MathType!MTEF!2!1!+-
% feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaaGOmamaaka
% aabaGaaG4maaWcbeaakiaaykW7daqadaqaaiaabogacaqGTbaacaGL
% OaGaayzkaaaaaa!3C7C!
2\sqrt 3 \,\left( {{\rm{cm}}} \right)\) với AB là đường kính của đường tròn đáy tâm O . Gọi M là điểm thuộc cung AB của đường tròn đáy sao cho \(% MathType!MTEF!2!1!+-
% feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaWaaecaaeaaca
% WGbbGaamOqaiaad2eaaiaawkWaaiabg2da9iaaiAdacaaIWaGaeyiS
% aalaaa!3D81!
\widehat {ABM} = 60^\circ \) . Thể tích của khối tứ diện ACDM là:
A.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamOvaiabg2
% da9iaaiodacaaMc8+aaeWaaeaacaqGJbGaaeyBamaaCaaaleqabaGa
% aG4maaaaaOGaayjkaiaawMcaaiaac6caaaa!3F22!
V = 3\,\left( {{\rm{c}}{{\rm{m}}^3}} \right).\)
B.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamOvaiabg2
% da9iaaiodacaaMc8+aaeWaaeaacaqGJbGaaeyBamaaCaaaleqabaGa
% aG4maaaaaOGaayjkaiaawMcaaiaac6caaaa!3F22!
V = 4\,\left( {{\rm{c}}{{\rm{m}}^3}} \right).\)
C.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamOvaiabg2
% da9iaaiodacaaMc8+aaeWaaeaacaqGJbGaaeyBamaaCaaaleqabaGa
% aG4maaaaaOGaayjkaiaawMcaaiaac6caaaa!3F22!
V = 6\,\left( {{\rm{c}}{{\rm{m}}^3}} \right).\)
D.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamOvaiabg2
% da9iaaiodacaaMc8+aaeWaaeaacaqGJbGaaeyBamaaCaaaleqabaGa
% aG4maaaaaOGaayjkaiaawMcaaiaac6caaaa!3F22!
V = 7\,\left( {{\rm{c}}{{\rm{m}}^3}} \right).\)
Câu 43
Tìm tất cả các giá trị thực của tham số m để hàm số \(% MathType!MTEF!2!1!+-
% feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamyEaiabg2
% da9iGacYgacaGGVbGaai4zamaabmaabaGaamiEamaaCaaaleqabaGa
% aGOmaaaakiabgkHiTiaaikdacaWGTbGaamiEaiabgUcaRiaaisdaai
% aawIcacaGLPaaaaaa!4379!
y = \log \left( {{x^2} - 2mx + 4} \right)\) có tập xác định là R .
A.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaWaamqaaqaabe
% qaaiaad2gacqGH+aGpcaaIYaaabaGaamyBaiabgYda8iabgkHiTiaa
% ikdaaaGaay5waaGaaiOlaaaa!3DFD!
\left[ \begin{array}{l}
m > 2\\
m < - 2
\end{array} \right..\)
B.
m = 2
C.
m < 2
D.
- 2 < m < 2
Câu 44
Cho hình nón tròn xoay có chiều cao h = 20(cm) , bán kính đáy r = 25(cm) . Một thiết diện đi qua đỉnh của hình nón có khoảng cách từ tâm đáy đến mặt phẳng chứa thiết diện là 12(cm) . Tính diện tích của thiết diện đó.
A.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaam4uaiabg2
% da9iaaiwdacaaIWaGaaGimaiaaykW7daqadaqaaiaabogacaqGTbWa
% aWbaaSqabeaacaaIYaaaaaGccaGLOaGaayzkaaGaaiOlaaaa!4094!
S = 500\,\left( {{\rm{c}}{{\rm{m}}^2}} \right).\)
B.
\(S = 300\,\left( {{\rm{c}}{{\rm{m}}^2}} \right).\)
C.
\(S = 400\,\left( {{\rm{c}}{{\rm{m}}^2}} \right).\)
D.
\(S = 406\,\left( {{\rm{c}}{{\rm{m}}^2}} \right).\)
Câu 45
Cho a, b, c là các số thực dương khác 1. Hình vẽ bên là đồ thị các hàm số \(% MathType!MTEF!2!1!+-
% feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamyEaiabg2
% da9iaadggadaahaaWcbeqaaiaadIhaaaGccaGGSaGaaGPaVlaadMha
% cqGH9aqpcaWGIbWaaWbaaSqabeaacaWG4baaaOGaaiilaiaaykW7ca
% WG5bGaeyypa0JaciiBaiaac+gacaGGNbWaaSbaaSqaaiaadogaaeqa
% aOGaamiEaaaa!4996!
y = {a^x},\,y = {b^x},\,y = {\log _c}x\)
A.
a < b < c
B.
c < b < a
C.
a < c < b
D.
c < a < b
Câu 46
Cho hình chóp S.ABC có đáy là tam giác ABC đều cạnh a , tam giác SBA vuông tại B , tam giác SAC vuông tại C. Biết góc giữa hai mặt phẳng (SAB) và (ABC) bằng \(% MathType!MTEF!2!1!+-
% feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaaGOnaiaaic
% dacqGHWcaSaaa!395A!
60^\circ\) . Tính thể tích khối chóp S.ABC theo a .
A.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaWaaSaaaeaada
% GcaaqaaiaaiodaaSqabaGccaWGHbWaaWbaaSqabeaacaaIZaaaaaGc
% baGaaGioaaaaaaa!3982!
\frac{{\sqrt 3 {a^3}}}{8}\)
B.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaWaaSaaaeaada
% GcaaqaaiaaiodaaSqabaGccaWGHbWaaWbaaSqabeaacaaIZaaaaaGc
% baGaaGymaiaaikdaaaaaaa!3A37!
\frac{{\sqrt 3 {a^3}}}{{12}}\)
C.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaWaaSaaaeaada
% GcaaqaaiaaiodaaSqabaGccaWGHbWaaWbaaSqabeaacaaIZaaaaaGc
% baGaaGOnaaaaaaa!3980!
\frac{{\sqrt 3 {a^3}}}{6}\)
D.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaWaaSaaaeaada
% GcaaqaaiaaiodaaSqabaGccaWGHbWaaWbaaSqabeaacaaIZaaaaaGc
% baGaaGinaaaaaaa!397E!
\frac{{\sqrt 3 {a^3}}}{4}\)
Câu 47
Số các giá trị nguyên của tham số m để phương trình \(% MathType!MTEF!2!1!+-
% feaahqart1ev3aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaciiBaiaac+
% gacaGGNbWaaSbaaSqaamaakaaabaGaaGOmaaadbeaaaSqabaGcdaqa
% daqaaiaadIhacqGHsislcaaIXaaacaGLOaGaayzkaaGaeyypa0Jaci
% iBaiaac+gacaGGNbWaaSbaaSqaaiaaikdaaeqaaOWaaeWaaeaacaWG
% TbGaamiEaiabgkHiTiaaiIdaaiaawIcacaGLPaaaaaa!47F9!
{\log _{\sqrt 2 }}\left( {x - 1} \right) = {\log _2}\left( {mx - 8} \right)\) có hai nghiệm phân biệt là
A.
3
B.
4
C.
5
D.
vô số
Câu 48
Cho hình chóp S.ABC có đáy là tam giác ABC vuông tại A góc \(% MathType!MTEF!2!1!+-
% feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaWaaecaaeaaca
% WGbbGaamOqaiaadoeaaiaawkWaaiabg2da9iaaiodacaaIWaGaeyiS
% aalaaa!3D74!
\widehat {ABC} = 30^\circ \) ; tam giác SBC là tam giác đều cạnh a và mặt phẳng (SAB) vuông góc mặt phẳng (ABC) . Khoảng cách từ A đến mặt phẳng (SBC) là:
A.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaWaaSaaaeaaca
% WGHbWaaOaaaeaacaaI2aaaleqaaaGcbaGaaGynaaaaaaa!388E!
\frac{{a\sqrt 6 }}{5}\)
B.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaWaaSaaaeaaca
% WGHbWaaOaaaeaacaaI2aaaleqaaaGcbaGaaG4maaaaaaa!388C!
\frac{{a\sqrt 6 }}{3}\)
C.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaWaaSaaaeaaca
% WGHbWaaOaaaeaacaaIZaaaleqaaaGcbaGaaG4maaaaaaa!3889!
\frac{{a\sqrt 3 }}{3}\)
D.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaWaaSaaaeaaca
% WGHbWaaOaaaeaacaaI2aaaleqaaaGcbaGaaGOnaaaaaaa!388F!
\frac{{a\sqrt 6 }}{6}\)
Câu 49
Cho hình chóp tứ giác đều S.ABCD có cạnh đáy bằng a . Gọi M, N lần lượt là trung điểm của SA và BC. Biết góc giữa MN và mặt phẳng (ABC) bằng \(% MathType!MTEF!2!1!+-
% feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaaGOnaiaaic
% dacqGHWcaSaaa!395A!
60^\circ \) . Khoảng cách giữa hai đường thẳng BC và DM là
A.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamyyaiaac6
% cadaGcaaqaamaalaaabaGaaGymaiaaiwdaaeaacaaI2aGaaGOmaaaa
% aSqabaGccaGGUaaaaa!3B69!
a.\sqrt {\frac{{15}}{{62}}} .\)
B.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamyyaiaac6
% cadaGcaaqaamaalaaabaGaaG4maiaaicdaaeaacaaIZaGaaGymaaaa
% aSqabaGccaGGUaaaaa!3B62!
a.\sqrt {\frac{{30}}{{31}}} .\)
C.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamyyaiaac6
% cadaGcaaqaamaalaaabaGaaGymaiaaiwdaaeaacaaI2aGaaGioaaaa
% aSqabaGccaGGUaaaaa!3B6F!
a.\sqrt {\frac{{15}}{{68}}} .\)
D.
\(% MathType!MTEF!2!1!+-
% feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamyyaiaac6
% cadaGcaaqaamaalaaabaGaaGymaiaaiwdaaeaacaaIXaGaaG4naaaa
% aSqabaGccaGGUaaaaa!3B69!
a.\sqrt {\frac{{15}}{{17}}} .\)
Câu 50
Cho a,b , c là các số thực thuộc đoạn \(% MathType!MTEF!2!1!+-
% feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaWaamWaaeaaca
% aIXaGaai4oaiaaikdaaiaawUfacaGLDbaaaaa!3A1C!
\left[ {1;2} \right]\) thỏa mãn \(% MathType!MTEF!2!1!+-
% feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaciiBaiaac+
% gacaGGNbWaa0baaSqaaiaaikdaaeaacaaIZaaaaOGaamyyaiabgUca
% RiGacYgacaGGVbGaai4zamaaDaaaleaacaaIYaaabaGaaG4maaaaki
% aadkgacqGHRaWkciGGSbGaai4BaiaacEgadaqhaaWcbaGaaGOmaaqa
% aiaaiodaaaGccaWGJbGaeyizImQaaGymaiaac6caaaa!4B0F!
\log _2^3a + \log _2^3b + \log _2^3c \le 1.\) Khi biểu thức \(% MathType!MTEF!2!1!+-
% feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
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P = {a^3} + {b^3} + {c^3} - 3\left( {{{\log }_2}{a^a} + {{\log }_2}{b^b} + {{\log }_2}{c^c}} \right)\) đạt giá trị lớn nhất thì giá trị của tổng a + b + c là
A.
3
B.
\(% MathType!MTEF!2!1!+-
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{3.2^{\frac{1}{{\sqrt[3]{3}}}}}\)
C.
4
D.
6